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-4x^2+6.13x-1=0
a = -4; b = 6.13; c = -1;
Δ = b2-4ac
Δ = 6.132-4·(-4)·(-1)
Δ = 21.5769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.13)-\sqrt{21.5769}}{2*-4}=\frac{-6.13-\sqrt{21.5769}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.13)+\sqrt{21.5769}}{2*-4}=\frac{-6.13+\sqrt{21.5769}}{-8} $
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